If you group the alternation, then you will get the expected behavior:
/^(a|b)$/
Your regex will find a a
at the start of the string (with ^a
branch) or b
at the end (with the b$
branch).
When you use ^(a|b)$
, the anchors are applied to the whole group and thus it will match a string that is equal to a
or b
.
Also, if you do not really need to capture the value, you may either use a non-capturing group, /^(?:a|b)$/
, or a n
modifier, /^(a|b)$/n
.
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