c++ - Is RVO (Return Value Optimization) applicable for all objects?

Question

Is RVO (Return Value Optimization) guaranteed or applicable for all objects and situations in C++ compilers (specially GCC)?

If answer is "no", what are the conditions of this optimization for a class/object? How can I force or encourage the compiler to do a RVO on a specific returned value?

Answer 1

Return Value Optimization can always be applied, what cannot be universally applied is Named Return Value Optimization. Basically, for the optimization to take place, the compiler must know what object is going to be returned at the place where the object is constructed.

In the case of RVO (where a temporary is returned) that condition is trivially met: the object is constructed in the return statement, and well, it is returned.

In the case of NRVO, you would have to analyze the code to understand whether the compiler can know or not that information. If the analysis of the function is simple, chances are that the compiler will optimize it (single return statement that does not contain a conditional, for example; multiple return statements of the same object; multiple return statements like T f() { if (condition) { T r; return r; } else { T r2; return r2; } } where the compiler knows that r or r2 will be returned...)

Note that you can only assume the optimization in simple cases, specifically, the example in wikipedia could actually be optimized by a smart enough compiler:

std::string f( bool x ) {
   std::string a("a"), b("b");
   if ( x ) return a; 
   else return b;
}

Can be rewritten by the compiler into:

std::string f( bool x ) {
   if ( x ) {
      std::string a("a"), b("b");
      return a;
   } else {
      std::string a("a"), b("b");
      return b;
   }
}

And the compiler can know at this time that in the first branch a is to be constructed in place of the returned object, and in the second branch the same applies to b. But I would not count on that. If the code is complex, assume that the compiler will not be able to produce the optimization.

EDIT: There is one case that I have not mentioned explicitly, the compiler is not allowed (in most cases even if it was allowed, it could not possibly do it) to optimize away the copy from an argument to the function to the return statement:

T f( T value ) { return value; } // Cannot be optimized away --but can be converted into
                                 // a move operation if available.