c++ - How to extract the source filename without path and suffix at compile time?

Question

Using both gcc with -std=c11 and g++ with -std=c++14.

E.g. for a file named src/dir/Hello.cxx it should expand to something like e.g.:

const char basename[] = "Hello";

or

const char basename[] = getStaticBasename(__FILE__);

as where getStaticBasename() is a macro (for C sources) or constexpr function (for C++ sources) which results to "Hello".

I have to avoid splitting the string from __FILE__ at runtime, because the path and suffix must not be compiled into the executable in any way.

The solution must be without dependencies to huge libraries such as boost.

As I have no makefiles, solutions like this cannot be used in my case.

Did one have a solution for that?

Edit 2015-07-02:

• I have no influence on how the compiler and linker was invoked (sometimes via makefile, sometimes from command line, or some IDE (Eclipse CDT managed make, Crossworks, Xcode et cetera. So the solution needs to be in code only.
• My use case is to provide some kind of "generic region identifier" for a small footprint logging solution. The application code (which uses my logger) should only #include <Joe/Logger.h> and within the later calls to e.g. LOG_DEBUG(...) I'll implicitely take use of the automatically generated "generic region identifier".
• My current solution is that the application code have to declare a JOE_LOG_FILE_REGION(Hello); (after #include <Joe/Logger.h>) before it could place LOG_DEBUG(...) in its code.

Answer 1

1. gcc builtin function can get the file name of a full path at compile time.

#define __FILENAME__ (__builtin_strrchr(__FILE__, '/') ? __builtin_strrchr(__FILE__, '/') + 1 : __FILE__)

or

#define __FILENAME__ (strrchr(__FILE__, '/') ? strrchr(__FILE__, '/') + 1 : __FILE__)

2. c++11 constexpr also can do this at compile time.

c++11 constexpr function can only use a return-statement.

example:

#include <stdio.h>

constexpr const char* str_end(const char *str) {
    return *str ? str_end(str + 1) : str;
}

constexpr bool str_slant(const char *str) {
    return *str == '/' ? true : (*str ? str_slant(str + 1) : false);
}

constexpr const char* r_slant(const char* str) {
    return *str == '/' ? (str + 1) : r_slant(str - 1);
}
constexpr const char* file_name(const char* str) {
    return str_slant(str) ? r_slant(str_end(str)) : str;
}

int main() {
    constexpr const char *const_file = file_name(__FILE__);
    puts(const_file);
    return 0;
}

source file name is foo/foo1/foo2/foo3/foo4.cpp

use g++ -o foo.exe foo/foo1/foo2/foo3/foo4.cpp -std=c++11 --save-temps to compile this file.

you can see this.

.file   "foo4.cpp"
        .section        .rodata
.LC0:
        .string "foo/foo1/foo2/foo3/foo4.cpp"
        .text
        .globl  main
        .type   main, @function
main:
.LFB4:
        .cfi_startproc
        pushq   %rbp
        .cfi_def_cfa_offset 16
        .cfi_offset 6, -16
        movq    %rsp, %rbp
        .cfi_def_cfa_register 6
        subq    $16, %rsp
        movq    $.LC0+19, -8(%rbp) 
        movl    $.LC0+19, %edi
        call    puts
        movl    $0, %eax
        leave
        .cfi_def_cfa 7, 8
        ret
        .cfi_endproc
.LFE4:
        .size   main, .-main
        .ident  "GCC: (Ubuntu 4.8.4-2ubuntu1~14.04.3) 4.8.4"
        .section        .note.GNU-stack,"",@progbits

movl $.LC0+19, %edi .LC0 + 19 is the address of file name string without path and suffix

3. c++14 constexpr function can do this in a simple way

#include <iostream>

constexpr const char* file_name(const char* path) {
    const char* file = path;
    while (*path) {
        if (*path++ == '/') {
            file = path;
        }
    }
    return file;
}

int main() {
    constexpr const char* file = file_name(__FILE__);
    std::cout << file << std::endl;
    return 0;
}

c++14 constexpr function can use loop and local variable.

the file_name function will replace with a address of const char * at compiler time. ~