Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
495 views
in Technique[技术] by (71.8m points)

traversal - Returning only simple paths in Neo4j Cypher query

Given a query like the following:

START n = node(123)
MATCH p = n-[r:LIKES*..3]->x
RETURN p;

The result paths that I get with the query above contain cycles.

How can I return only simple paths?

Given this example:

  • How can I avoid paths with repeated nodes like: [Neo, Morpheus, Trinity, Morpheus, Neo]
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Specifying the uniqueness of paths is a planned feature of cypher.

So right now we have to ascertain that no node is a duplicate in the path.

There is an ALL predicate that must hold true for all elements of a collection (which a path is). And with filter you can extract the elements of an collection for that a certain condition holds true.

START neo=node(1) 
MATCH path= neo-[r:KNOWS*..4]->other 
WHERE ALL(n in nodes(path) where 
          1=length(filter(m in nodes(path) : m=n))) 
RETURN neo, LENGTH(path) AS length, EXTRACT(p in NODES(path) : p.name), other 
ORDER BY length

So what I did was:

  • For all nodes of the path n
  • Filter the path for the nodes that are equal to n
  • determine the length of that collection
  • assert with ALL that it has to be ONE for each n

see: http://console.neo4j.org/r/dpalbl


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...