css - Make CSS3 triangle with linear gradient

Question

I need to create button with triangle on one side (like this http://css-tricks.com/triangle-breadcrumbs/) with linear vertical gradient and border, and I want to use pure CSS3. It's ok if I need 45deg "triangle", I just write smth like this

.button:after {
    -webkit-transform: rotate(45deg);
    background: -webkit-linear-gradient(-45deg, #fff, #000);
    content: '';
    width: 2em;
    height: 2em;
    display: block;
}

and hide half of that pseudo-element under .button (so only another half of it is visible, like a triangle).

But if I need another angle (e.g. more steep) - I can't make it with standart XY rotate and scale. I can use e.g. 2 divs, one for top half of triangle and one for bottom, but there might be a problem with border and gradient.

Maybe it's possible to do that with multiple gradients with color stops?

Answer 1

So I know that you want to do this with CSS, but I always do this in SVG:

<svg width="100%" height="100%" version="1.1" xmlns="http://www.w3.org/2000/svg">

<defs>
<linearGradient id="fill" x1="0%" y1="0%" x2="0%" y2="100%">
<stop offset="0%" style="stop-color:rgb(224,224,224);stop-opacity:1"/>
<stop offset="100%" style="stop-color:rgb(153,153,153);stop-opacity:1"/>
</linearGradient>
</defs>

<path d="M 0 0 L 64 0 L 32 64 z" stroke="colourname" fill="url(#fill)"/>

</svg>

You can embed it as so:

<img src="triangle.svg" alt="Triangle" class="triangle" />

You could also make the toggle image in the same way, and toggle it using JavaScript or jQuery:

$(".triangle").click(function()
{
    if($(this).attr("src") == "triangle.svg")
        $(this).attr("src", "triangledown.svg");

    else $(this).attr("src", "triangle.svg");
});