If you want to trim all spaces, only in lines that have a comma, and use awk
, then the following will work for you:
awk -F, '/,/{gsub(/ /, "", $0); print} ' input.txt
If you only want to remove spaces in the second column, change the expression to
awk -F, '/,/{gsub(/ /, "", $2); print$1","$2} ' input.txt
Note that gsub
substitutes the character in //
with the second expression, in the variable that is the third parameter - and does so in-place
- in other words, when it's done, the $0
(or $2
) has been modified.
Full explanation:
-F, use comma as field separator
(so the thing before the first comma is $1, etc)
/,/ operate only on lines with a comma
(this means empty lines are skipped)
gsub(a,b,c) match the regular expression a, replace it with b,
and do all this with the contents of c
print$1","$2 print the contents of field 1, a comma, then field 2
input.txt use input.txt as the source of lines to process
EDIT I want to point out that @BMW's solution is better, as it actually trims only leading and trailing spaces with two successive gsub
commands. Whilst giving credit I will give an explanation of how it works.
gsub(/^[ ]+/,"",$2); - starting at the beginning (^) replace all (+ = zero or more, greedy)
consecutive tabs and spaces with an empty string
gsub(/[ ]+$/,"",$2)} - do the same, but now for all space up to the end of string ($)
1 - ="true". Shorthand for "use default action", which is print $0
- that is, print the entire (modified) line