javascript - creating tasks using a loop [gulp]

Question

I'm trying to dynamically create tasks (minify and concat) based on jsFiles object. The key will give the destination file name and the array contains the src files. When I run gulp I see all the tasks names being ran but it only writes the last key which is group2.js in this case. What's wrong here?

// imports here

var jsFiles = 
{
    group1:[file1.js,file2.js],
    group2:[file2.js,file3.js]
};

for (var key in jsFiles)
{
    gulp.task(key, function() {
        return gulp.src(jsFiles[key])
        .pipe(jshint())
        .pipe(uglify())
        .pipe(concat(key + '.js'))  // <- HERE
        .pipe(gulp.dest('public/js'));
    });
}

var defaultTasks = [];
for (var key in jsFiles)
{
    defaultTasks.push(key);
}
gulp.task('default', defaultTasks);

Answer 1

Another option is to use functional array looping functions combined with Object.keys, like so:

var defaultTasks = Object.keys(jsFiles);

defaultTasks.forEach(function(taskName) {
   gulp.task(taskName, function() {
       return gulp.src(jsFiles[taskName])
          .pipe(jshint())
          .pipe(uglify())
          .pipe(concat(key + '.js'))
          .pipe(gulp.dest('public/js'));
   });
});

I feel like this is a little cleaner, because you have the loop and the function in the same place, so it's easier to maintain.