Isn't Insertion sort O(n^2) > Quicksort O(n log n)...so for a small n, won't the relation be the same?
O(n^2)
O(n log n)
Big-O Notation describes the limiting behavior when n is large, also known as asymptotic behavior. This is an approximation. (See http://en.wikipedia.org/wiki/Big_O_notation)
Insertion sort is faster for small n because Quick Sort has extra overhead from the recursive function calls. Insertion sort is also more stable than Quick sort and requires less memory.
This question describes some further benefits of insertion sort. ( Is there ever a good reason to use Insertion Sort? )
2.1m questions
2.1m answers
60 comments
57.0k users