I was reading about Empty Base Optimization(EBO). While reading, the following questions popped up in my mind:
What is the point of using Empty class as base class when it contributes nothing to the derived classes (neither functionality-wise, nor data-wise)?
In this article, I read this:
//S is empty
class struct T : S
{
??????int x;
};
[...]
Notice that we didn’t lose any data or
code accuracy: when you create a
standalone object of type S, the
object’s size is still 1 (or more) as
before; only when S is used as base
class of another class does its memory
footprint shrink to zero. To realize
the impact of this saving, imagine a
vector that contains 125,000
objects. The EBO alone saves half a
megabyte of memory!
Does it mean that if we don't use "S" as base class of "T", we would necessarily consume double of megabyte of memory? I think, the article compares two different scenarios which I don't think is correct.
I would like to know a real scenario when EBO can proven to be useful.(means, in the same scenario, we would necessarily be at loss IF we don't use EBO!).
Please note that if your answer contains explanations like this :
The whole point is that an empty class has non-zero size, but when derived or deriving it can have zero size, then I'm NOT asking that, as I know that already. My question is, why would anyone derive his class from an empty class in the first place? Even if he doesn't derive and simply writes his class (without any empty base), is he at loss in ANY way?
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