I just found out that this is illegal in C++ (but legal in C):
#include <stdio.h>
#include <stdlib.h>
#define ARRAY_LENGTH(A) (sizeof(A) / sizeof(A[0]))
int accumulate(int n, const int (*array)[])
{
int i;
int sum = 0;
for (i = 0; i < n; ++i) {
sum += (*array)[i];
}
return sum;
}
int main(void)
{
int a[] = {3, 4, 2, 4, 6, 1, -40, 23, 35};
printf("%d
", accumulate(ARRAY_LENGTH(a), &a));
return 0;
}
It compiles without problems using gcc -std=c89 -pedantic
but fails to compile using g++
. When I try to compile it using g++
I get these error messages:
main.cpp:5:37: error: parameter 'array' includes pointer to array of unknown bound 'int []'
int accumulate(int n, int (*array)[])
^
main.cpp: In function 'int main()':
main.cpp:18:50: error: cannot convert 'int (*)[9]' to 'int (*)[]' for argument '2' to 'int accumulate(int, int (*)[])'
printf("%d
", accumulate(ARRAY_LENGTH(a), &a));
I have been using this in my C code for a long time and I had no idea that it was illegal in C++. To me this seems like a useful way to document that a function takes an array whose size is not known before hand.
I want to know why this is legal C but invalid C++. I also wonder what it was that made the C++ committee decide to take it away (and breaking this compatibility with C).
So why is this legal C code but illegal C++ code?
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