The following code:
<?php
try {
$dbh = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password);
echo "Connection is successful!<br/>";
$sql = "SELECT * FROM users";
$users = $dbh->query($sql);
foreach ($users as $row) {
print $row["name"] . "-" . $row["sex"] ."<br/>";
}
foreach ($users as $row) {
print $row["name"] . "-" . $row["sex"] ."<br/>";
}
$dbh = null;
}
catch (PDOexception $e) {
echo "Error is: " . $e-> etmessage();
}
Output:
Connection is successful!
person A-male
person B-female
Running "foreach" twice is not my purpose, I'm just curious why TWO "foreach" statements only output the result once?
Following is the similar case:
<?php
try {
$dbh = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password);
echo "Connection is successful!<br/>";
$sql = "SELECT * FROM users";
$users = $dbh->query($sql);
foreach ($users as $row) {
print $row["name"] . "-" . $row["sex"] ."<br/>";
}
echo "<br/>";
$result = $users->fetch(PDO::FETCH_ASSOC);
foreach($result as $key => $value) {
echo $key . "-" . $value . "<br/>";
}
$dbh = null;
}
catch (PDOexception $e) {
echo "Error is: " . $e-> etmessage();
}
Output:
Connection is successful!
person A-male
person B-female
SCREAM: Error suppression ignored for
Warning: Invalid argument supplied for foreach()
But when I delete the first "foreach" from the above codes, the output will become normal:
<?php
try {
$dbh = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password);
echo "Connection is successful!<br/>";
$sql = "SELECT * FROM users";
$users = $dbh->query($sql);
echo "<br/>";
$result = $users->fetch(PDO::FETCH_ASSOC);
foreach($result as $key => $value) {
echo $key . "-" . $value . "<br/>";
}
$dbh = null;
}
catch (PDOexception $e) {
echo "Error is: " . $e-> etmessage();
}
Output:
Connection is successful!
user_id-0000000001
name-person A
sex-male
Why does this happen?
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…