Re.search only matches the first occurrence within the string. You want finditer or findall.
re.search
Scan through string looking for the first location where the regular expression pattern produces a match, and return a corresponding MatchObject instance. Return None if no position in the string matches the pattern; note that this is different from finding a zero-length match at some point in the string.
Finditer returns match objects for all locations within the target string, yielding an iterator, while findall returns the substrings for all matches.
>>> import re
>>> re.findall('a', 'ababababa')
['a', 'a', 'a', 'a', 'a']
>>> x = list(re.finditer('a', 'ababababa'))
>>> x
[<_sre.SRE_Match object; span=(0, 1), match='a'>,
<_sre.SRE_Match object; span=(2, 3), match='a'>,
<_sre.SRE_Match object; span=(4, 5), match='a'>,
<_sre.SRE_Match object; span=(6, 7), match='a'>,
<_sre.SRE_Match object; span=(8, 9), match='a'>]
>>> x[0].group()
'a'
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