if statement - Python if with many or in a contracted form

Question

I'm learning python and I found myself lost trying to create a an if statement that should be true if the user input y or yes.

#!/usr/bin/env python3

user_input = input('Would you like to go on?')
lowui = user_input.lower

if lowui == ('y' or 'yes'):
   print('You want to go on')
else
   print('See you later, bye')

The problem is that it becomes true only if I type y but not for yes. If I remove the parenthesis it becomes always false. Ok, I can do a workaround like

if lowui == 'y' or lowui == 'yes':

but I was wondering if there is any trick that don't force me to write so many times tha variable.
Thank you in advance.

Answer 1

Change it to

if lowui in ('y', 'yes'):

Also this is wrong:

lowui = user_input.lower

it should be:

lowui = user_input.lower() # Actually call the lower function