Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
677 views
in Technique[技术] by (71.8m points)

html - symetric div with background image without clip-path

hi guys i have two differents div with background image, as you see in the picture. They are symetrics. i achieved that with clip-path, but as know it's not well supported by all browsers, could you guys give me an alternative to achieve that to be more compatible. Your help would be appreciated. Thx!

body {
  margin: 0;
  /* background: red; */
  padding: 100px 0;
}

.container_first {
  clip-path: polygon(0 0, 100% 14%, 100% 90%, 0% 100%);
  background-image: url(images/img12.jpg);
  min-height: 500px;
  width: 100%;
  background-size: cover;
  background-repeat: no-repeat;
}

.container_second {
  margin-top: -54px;

  clip-path: polygon(0% 10%, 100% 0, 100% 100%, 0 86%);
  background-image: url(images/img22.jpg);
  min-height: 500px;
  width: 100%;
  background-size: cover;
  background-repeat: no-repeat;
}

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Use skew transformation:

.first,
.second {
  height:300px;
  transform-origin:left;
  overflow:hidden;
}

.first {
  transform:skewY(4deg);
}
.first > div {
  height:100%;
  background:url(https://picsum.photos/id/10/800/800) center/cover;
  transform:skewY(-4deg);
  transform-origin:left;
}
.second {
  transform:skewY(-4deg);
}
.second > div {
  height:100%;
  background:url(https://picsum.photos/id/1045/800/800) center/cover;
  transform:skewY(8deg); /* twice the skew here so you may need another skew for the content*/
  transform-origin:right;
}
<div class="first">
  <div></div>
</div>
<div class="second">
  <div></div>
</div>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...