Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
586 views
in Technique[技术] by (71.8m points)

html - What does the shrink-to-fit viewport meta attribute do?

I'm having trouble finding documentation for this. Is it Safari specific?

There was a recent bug in iOS 9 (here), the solution to which is adding shrink-to-fit=no to the viewport meta.

What does this code do?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

It is Safari specific, at least at time of writing, being introduced in Safari 9.0. From the "What's new in Safari?" documentation for Safari 9.0:

Viewport Changes

Viewport meta tags using "width=device-width" cause the page to scale down to fit content that overflows the viewport bounds. You can override this behavior by adding "shrink-to-fit=no" to your meta tag as shown below. The added value will prevent the page from scaling to fit the viewport.

<meta name="viewport" content="width=device-width, initial-scale=1.0, shrink-to-fit=no">

In short, adding this to the viewport meta tag restores pre-Safari 9.0 behaviour.

Example

Here's a worked visual example which shows the difference upon loading the page in the two configurations.

The red section is the width of the viewport and the blue section is positioned outside the initial viewport (eg left: 100vw). Note how in the first example the page is zoomed to fit when shrink-to-fit=no is omitted (thus showing the out-of-viewport content) and the blue content remains off screen in the latter example.

The code for this example can be found at https://codepen.io/davidjb/pen/ENGqpv.

Without shrink-to-fit specified

Without shrink-to-fit=no

With shrink-to-fit=no

With shrink-to-fit=no


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...