Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
469 views
in Technique[技术] by (71.8m points)

sql server - Calculate Time Difference Between Two Rows

I have a table that contains the following:

DataDate                 Value
2010-03-01 08:31:32.000  100
2010-03-01 08:31:40.000  110
2010-03-01 08:31:42.000  95
2010-03-01 08:31:45.000  101
.                        .
.                        .
.                        .

I need to multiply the value column by the difference in time between the current and previous rows and sum that for the entire day.

I currently have the data set up to come in every 10 seconds which makes for a simple conversion in the query:

SELECT Sum((Value/6) FROM History WHERE DataDate BETWEEN @startDate and @endDate

Where @startDate and @endDate are today's date at 00:00:00 and 11:59:59.

Before I set the data to be collected every 10 seconds it was collected whenever the Value changed. There aren't any duplicate entries in terms of time, the minimum time difference is 1 second.

How can I set up a query to get the elapsed time between rows for the case when I don't know the time interval between readings?

I am using SQL Server 2005.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)
WITH    rows AS
        (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY DataDate) AS rn
        FROM    mytable
        )
SELECT  DATEDIFF(second, mc.DataDate, mp.DataDate)
FROM    rows mc
JOIN    rows mp
ON      mc.rn = mp.rn - 1

In SQL Server 2012+:

SELECT  DATEDIFF(second, pDataDate, dataDate)
FROM    (
        SELECT  *,
                LAG(dataDate) OVER (ORDER BY dataDate) pDataDate
        FROM    rows
        ) q
WHERE   pDataDate IS NOT NULL

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...