You can use atexit for this, and register any clean up tasks to be run when your program exits.
atexit.register(func[, *args[, **kargs]])
In your cleanup process, you can also implement your own wait, and kill it when a your desired timeout occurs.
>>> import atexit
>>> import sys
>>> import time
>>>
>>>
>>>
>>> def cleanup():
... timeout_sec = 5
... for p in all_processes: # list of your processes
... p_sec = 0
... for second in range(timeout_sec):
... if p.poll() == None:
... time.sleep(1)
... p_sec += 1
... if p_sec >= timeout_sec:
... p.kill() # supported from python 2.6
... print 'cleaned up!'
...
>>>
>>> atexit.register(cleanup)
>>>
>>> sys.exit()
cleaned up!
Note -- Registered functions won't be run if this process (parent process) is killed.
The following windows method is no longer needed for python >= 2.6
Here's a way to kill a process in windows. Your Popen object has a pid attribute, so you can just call it by success = win_kill(p.pid) (Needs pywin32 installed):
def win_kill(pid):
'''kill a process by specified PID in windows'''
import win32api
import win32con
hProc = None
try:
hProc = win32api.OpenProcess(win32con.PROCESS_TERMINATE, 0, pid)
win32api.TerminateProcess(hProc, 0)
except Exception:
return False
finally:
if hProc != None:
hProc.Close()
return True
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