Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
642 views
in Technique[技术] by (71.8m points)

validation - How to check if bootstrap modal is open, so I can use jquery validate?

I need to make a validation only if a modal is open, because if I open it, and then I close it, and the I press the button that opens the modal it doesn't work because it is making the jquery validation, but not showing because the modal was dismissed.

So I want to ad a jquery if modal is open so the i do validate, is this possible?

<script>
$(document).ready(function(){

var validator =$('#form1').validate(
 {
  ignore: "",
  rules: {

usu_login: {
  required: true
},
usu_password: {
  required: true
},
usu_email: {
  required: true
},
usu_nombre1: {
  required: true
},
usu_apellido1: {
  required: true
},
usu_fecha_nac: {
  required: true
},
usu_cedula: {
  required: true
},
usu_telefono1: {
  required: true
},
rol_id: {
  required: true
},
dependencia_id: {
  required: true
},
  },

  highlight: function(element) {
$(element).closest('.grupo').addClass('has-error');
        if($(".tab-content").find("div.tab-pane.active:has(div.has-error)").length == 0)
        {
            $(".tab-content").find("div.tab-pane:hidden:has(div.has-error)").each(function(index, tab)
            {
                var id = $(tab).attr("id");
        
                $('a[href="#' + id + '"]').tab('show');
            });
        }
  },
  unhighlight: function(element) {
$(element).closest('.grupo').removeClass('has-error');
  }
 });

}); // end document.ready

</script>
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

To avoid the race condition @GregPettit mentions, one can use:

($("element").data('bs.modal') || {})._isShown    // Bootstrap 4
($("element").data('bs.modal') || {}).isShown     // Bootstrap <= 3

// or, with the optional chaining operator (?.)
$("element").data('bs.modal')?._isShown    // Bootstrap 4
$("element").data('bs.modal')?.isShown     // Bootstrap <= 3

as discussed in Twitter Bootstrap Modal - IsShown.

When the modal is not yet opened, .data('bs.modal') returns undefined, hence the || {} - which will make isShown the (falsy) value undefined. If you're into strictness one could do ($("element").data('bs.modal') || {isShown: false}).isShown


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...