Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
337 views
in Technique[技术] by (71.8m points)

c++ - Why do functions/objects inside anonymous namespace have external linkage?

Why don't symbols (functions and variables) that are defined in an anonymous namespace have internal linkage as with static keyword? If a function is not visible/accessible outside, what is the reason to have external linkage?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

In C++03, names with internal linkage were forbidden from being used as template arguments[*]. So, names of most things in unnamed namespaces had external linkage to allow their use with templates. You could explicitly give a name internal linkage in an unnamed namespace by declaring it static, same as in a named or global namespace.

Both things changed in C++11 -- names in unnamed namespaces have internal linkage by default (3.5/4), and names with internal linkage can be used as template arguments.

[*] for types, it must have external linkage. For objects and functions, it must have external linkage if its address is used as a template argument, although it's OK for example to use as a template argument the value of a const integer with internal linkage.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

2.1m questions

2.1m answers

60 comments

57.0k users

...