operator precedence - Order of execution of parameters guarantees in Java?

Question

Given the following function call in C:

fooFunc( barFunc(), bazFunc() );

The order of execution of barFunc and BazFunc is not specified, so barFunc() may be called before bazFunc() or bazFunc() before barFunc() in C.

Does Java specify an order of execution of function argument expressions or like C is that unspecified?

Answer 1

From the Java Language Specification (on Expressions):

15.7.4 Argument Lists are Evaluated Left-to-Right

In a method or constructor invocation or class instance creation expression, argument expressions may appear within the parentheses, separated by commas. Each argument expression appears to be fully evaluated before any part of any argument expression to its right.