range - Python: Checking to which bin a value belongs

Question

I have a list of values and a list of bin edges. Now I need to check for all values to what bin they belong to. Is there a more pythonic way than iterating over the values and then over the bins and checking if the value belongs to the current bin, like:

my_list = [3,2,56,4,32,4,7,88,4,3,4]
bins = [0,20,40,60,80,100]

for i in my_list:
    for j in range(len(bins)):
        if bins(j) < i < bins(j+1):
            DO SOMETHING

This doesn't look very pretty to me. Thanks!

Answer 1

Probably too late, but for future reference, numpy has a function that does just that:

http://docs.scipy.org/doc/numpy/reference/generated/numpy.digitize.html

>>> my_list = [3,2,56,4,32,4,7,88,4,3,4]
>>> bins = [0,20,40,60,80,100]
>>> np.digitize(my_list,bins)
array([1, 1, 3, 1, 2, 1, 1, 5, 1, 1, 1])

The result is an array of indexes corresponding to the bin from bins that each element from my_list belongs too. Note that the function will also bin values that fall outside of your first and last bin edges:

>>> my_list = [-5,200]
>>> np.digitize(my_list,bins)
array([0, 6])

And Pandas has something like it too:

http://pandas.pydata.org/pandas-docs/dev/basics.html#discretization-and-quantiling

>>> pd.cut(my_list, bins)
Categorical: 
array(['(0, 20]', '(0, 20]', '(40, 60]', '(0, 20]', '(20, 40]', '(0, 20]',
       '(0, 20]', '(80, 100]', '(0, 20]', '(0, 20]', '(0, 20]'], dtype=object)
Levels (5): Index(['(0, 20]', '(20, 40]', '(40, 60]', '(60, 80]',
                   '(80, 100]'], dtype=object)