Is a struct's address the same as its first member's address?
Yes, this is actually mandated by the C and C++ standards. From the C standard:
6.7.2.1-13. A pointer to a structure object, suitably converted, points to its initial member
The size of your struct
should be two bytes. You should not convert a pointer to it to char*
, though: instead, you should use memcpy
to copy your Bitmask
into the buffer that you send over the network.
EDIT Since you use scatter-gather I/O with iovec
, you do not need to cast Bitmask
to anything: iov_base
is void*
, so you can simply set iov[0].iov_base = header;
Note: This works only as long as your struct
does not contain virtual functions, base classes, etc. (thanks, Timo).
EDIT2
In order to get {0x81, 0x05} in your struct
, you should change the order of structure elements as follows:
struct Bitmask {
unsigned char opcode: 4;
unsigned char rsv3: 1;
unsigned char rsv2: 1;
unsigned char rsv1: 1;
unsigned char fin: 1;
unsigned char payload_length: 7;
unsigned char mask: 1;
}
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