Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
474 views
in Technique[技术] by (71.8m points)

c - kill a process started with popen

After opening a pipe to a process with popen, is there a way to kill the process that has been started? (Using pclose is not what I want because that will wait for the process to finish, but I need to kill it.)

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Don't use popen(), write your own wrapper that does what you'd like.

It's fairly straightforward to fork(), and then replace stdin & stdout by using dup2(), and then calling exec() on your child.

That way, your parent will have the exact child PID, and you can use kill() on that.

Google search for "popen2() implementation" for some sample code on how to implement what popen() is doing. It's only a dozen or so lines long. Taken from dzone.com we can see an example that looks like this:

#define READ 0
#define WRITE 1

pid_t
popen2(const char *command, int *infp, int *outfp)
{
    int p_stdin[2], p_stdout[2];
    pid_t pid;

    if (pipe(p_stdin) != 0 || pipe(p_stdout) != 0)
        return -1;

    pid = fork();

    if (pid < 0)
        return pid;
    else if (pid == 0)
    {
        close(p_stdin[WRITE]);
        dup2(p_stdin[READ], READ);
        close(p_stdout[READ]);
        dup2(p_stdout[WRITE], WRITE);

        execl("/bin/sh", "sh", "-c", command, NULL);
        perror("execl");
        exit(1);
    }

    if (infp == NULL)
        close(p_stdin[WRITE]);
    else
        *infp = p_stdin[WRITE];

    if (outfp == NULL)
        close(p_stdout[READ]);
    else
        *outfp = p_stdout[READ];

    return pid;
}

NB: Seems like popen2() is what you want, but my distribution doesn't seem to come with this method.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...