Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
561 views
in Technique[技术] by (71.8m points)

linux - How to get time since file was last modified in seconds with bash?

I need to get the time in seconds since a file was last modified. ls -l doesn't show it.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

The GNU implementation of date has an -r option to print the last modification date of a file instead of the current date. And we can use the format specifier %s to get the time in seconds, which is convenient to compute time differences.

lastModificationSeconds=$(date +%s -r file.txt)
currentSeconds=$(date +%s)

And then you can use arithmetic context to compute the difference, for example:

((elapsedSeconds = currentSeconds - lastModificationSeconds))
# or
elapsedSeconds=$((currentSeconds - lastModificationSeconds))

You could also compute and print the elapsed seconds directly without temporary variables:

echo $(($(date +%s) - $(date +%s -r file.txt)))

Unfortunately the BSD implementation of date (for example in Mac OS X) doesn't support the -r flag. To get the last modification seconds, you can use the stat command instead, as other answers suggested. Once you have that, the rest of the procedure is the same to compute the elapsed seconds.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...