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in Technique[技术] by (71.8m points)

php - How can I build a condition based query in Laravel?

I can do this in Code Igniter:

$this->db->select();
$this->from->('node');
if ($published == true)
{
    $this->db->where('published', 'true');
}
if (isset($year))
{
    $this->db->where('year >', $year);
}
$this->db->get();

How can this code be translated so that it works in Laravel?

See Question&Answers more detail:os

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1 Answer

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by (71.8m points)

In Fluent you can do:

$query = DB::table('node');

if ($published == true)
    $query->where('published', '=', 1);

if (isset($year))
    $query->where('year', '>', $year);

$result = $query->get();

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