As noted in Morgan's answer this will only produce a single random bit. The number of bits in the LFSR only set how many values you get before the sequence repeats. If you want an N bit random number you have to run the LFSR for N cycles. However, if you want a new number every clock cycle the other option is to unroll the loop and predict what the number will be in N cycles. Repeating Morgan's example below, but to get a 5 bit number each cycle:
module fibonacci_lfsr_5bit(
input clk,
input rst_n,
output reg [4:0] data
);
reg [4:0] data_next;
always @* begin
data_next[4] = data[4]^data[1];
data_next[3] = data[3]^data[0];
data_next[2] = data[2]^data_next[4];
data_next[1] = data[1]^data_next[3];
data_next[0] = data[0]^data_next[2];
end
always @(posedge clk or negedge rst_n)
if(!rst_n)
data <= 5'h1f;
else
data <= data_next;
endmodule
Edit: Added a new version below which doesn't require you to do the math. Just put it in a loop and let the synthesis tool figure out the logic:
module fibonacci_lfsr_nbit
#(parameter BITS = 5)
(
input clk,
input rst_n,
output reg [4:0] data
);
reg [4:0] data_next;
always_comb begin
data_next = data;
repeat(BITS) begin
data_next = {(data_next[4]^data_next[1]), data_next[4:1]};
end
end
always_ff @(posedge clk or negedge reset) begin
if(!rst_n)
data <= 5'h1f;
else
data <= data_next;
end
end
endmodule
I would like to make the LFSR length parameterizable as well, but that is much more difficult since the feedback taps don't follow a simple pattern.
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