I'm trying to write a variadic template constexpr
function which calculates sum of the template parameters given. Here's my code:
template<int First, int... Rest>
constexpr int f()
{
return First + f<Rest...>();
}
template<int First>
constexpr int f()
{
return First;
}
int main()
{
f<1, 2, 3>();
return 0;
}
Unfortunately, it does not compile reporting an error message error C2668: 'f': ambiguous call to overloaded function
while trying to resolve f<3,>()
call.
I also tried to change my recursion base case to accept 0 template arguments instead of 1:
template<>
constexpr int f()
{
return 0;
}
But this code also does not compile (message error C2912: explicit specialization 'int f(void)' is not a specialization of a function template
).
I could extract first and second template arguments to make this compile and work, like this:
template<int First, int Second, int... Rest>
constexpr int f()
{
return First + f<Second, Rest...>();
}
But this does not seem to be the best option. So, the question is: how to write this calculation in an elegant way?
UP: I also tried to write this as a single function:
template<int First, int... Rest>
constexpr int f()
{
return sizeof...(Rest) == 0 ? First : (First + f<Rest...>());
}
And this also does not work: error C2672: 'f': no matching overloaded function found
.
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