Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
762 views
in Technique[技术] by (71.8m points)

python - How to click a link that has javascript:__doPostBack in href?

I am writing a screen scraper script in python with module 'mechanize' and I would like to use the mechanize.click_link() method on a link that has javascript:__doPostBack in href. I believe the page I am trying to parse is using AJAX.

Note: mech is the mechanize.Browser()

>>> next_link.__class__.__name__
'Link'
>>> next_link
Link(base_url='http://www.citius.mj.pt/Portal/consultas/ConsultasDistribuicao.aspx', url="javascript:__doPostBack('ctl00$ContentPlaceHolder1$Pager1$lnkNext','')", text='2', tag='a', attrs=[('id', 'ctl00_ContentPlaceHolder1_Pager1_lnkNext'), ('title', 'Pxc3xa1gina seguinte: 2'), ('href', "javascript:__doPostBack('ctl00$ContentPlaceHolder1$Pager1$lnkNext','')")])
>>> req = mech.click_link(next_link)
>>> req
<urllib2.Request instance at 0x025BEE40>
>>> req.has_data()
False

I would like to retrieve the page source after clicking the link.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

I don't use mechanize, but I do a lot of web scraping myself with python.

When I run into a javascript function like __doPostBack, I do the following:
I access the web site in Firefox, and use the HttpFox extension to see the parameters of the POST request the browser sent to the web server when clicking the relevant link.
I then build the same request in python using urllib.parse.urlencode to build the query strings and POST data I need.
Sometimes the website uses cookies as well, so I just use python's http.cookiejar.

I have used this technique successfully several times.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...