There is nothing wrong in your example (except that you should add a semi-colon after the cin.tie(0)
line), nor with the way iostream objects work.
tie()
simply guarantees the flushing of cout
before cin
executes an input. This is useful for the user to see the question before being asked for the answer.
However, if you un-tie()
the cin
from cout
, there is no guarantee that the buffer of the cout
is flushed. But there is no guarantee that the buffer is un-flushed neither. In fact, if the computer has enough resources, it will flush the cout
buffer immediately, so this occurs before cin
asking for the input. This is the case in your example.
So, everything works well. Except that after cin.tie(0)
, there is no guarantee that the flush-ing will occur. However, in 99% of the cases, that flush-ing will still occur (but it is no longer guaranteed).
In theory, if tied, cin
and cout
could share the same buffer. But, I think no implementation does that. One reason is that the two may be un-tie()d.
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