Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
400 views
in Technique[技术] by (71.8m points)

process a list of files with a specific extension name in matlab

How can I process all the files with ".xyz" extension in a folder? The basic idea is that I want a list of file names and then a for loop to load each file.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

As others have already mentioned, you should use the DIR function to list files in a directory.

If you are still looking, here is an example to show how to use the function:

dirName = 'C:pathofolder';              %# folder path
files = dir( fullfile(dirName,'*.xyz') );   %# list all *.xyz files
files = {files.name}';                      %'# file names

data = cell(numel(files),1);                %# store file contents
for i=1:numel(files)
    fname = fullfile(dirName,files{i});     %# full path to file
    data{i} = myLoadFunction(fname);        %# load file
end

Of course, you would have to supply the function that actually reads and parses the XYZ files.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...