I am using a SynchronisedQueue
to communicate between threads. I found that destroying the thread object when the attaching thread is waiting on a condition variable would cause the program crash. This can be corrected by calling detach()
before the thread destruction. But I am wondering what happens exactly when a thread waiting a conditional variable got terminated. Is there another way to use condition variable to avoid this?
#include <queue>
#include <thread>
#include <mutex>
#include <condition_variable>
template <typename Type> class SynchronisedQueue {
public:
void Enqueue(Type const & data) {
std::unique_lock<std::mutex> lock(mutex_);
queue_.push(data);
condition_.notify_one();
}
Type Dequeue() {
std::unique_lock<std::mutex> lock(mutex_);
while (queue_.empty())
condition_.wait(lock);
Type result = queue_.front();
queue_.pop();
return result;
}
private:
std::queue<Type> queue_;
std::mutex mutex_;
std::condition_variable condition_;
};
class Worker {
public:
Worker(SynchronisedQueue<int> * queue) : queue_(queue) {}
void operator()() {
queue_->Dequeue(); // <-- The thread waits here.
}
private:
SynchronisedQueue<int> * queue_;
};
int main() {
auto queue = new SynchronisedQueue<int>();
Worker worker(queue);
std::thread worker_thread(worker);
worker_thread.~thread(); // <-- Crashes the program.
return 0;
}
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