It may be that the type of similarObject has overloaded operator* and so it returns something whose address you're passing to dynamic_cast.
&(*x) and x may not be always the same thing. For example, think of iterator:
std::map<int, int>::iterator it = v.begin();
Then it and &(*it) are two different thing:
- The type of
it is std::map<int, int>::iterator
- The type of
&(*it) is std::pair<int,int>*
They're not at all same. Similar thing may happen with your code-snippet as well.
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