Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
357 views
in Technique[技术] by (71.8m points)

delegates - C# compile error: "Invoke or BeginInvoke cannot be called on a control until the window handle has been created."

I just posted a question about how to get a delegate to update a textbox on another form. Just when I thought I had the answer using Invoke...this happens. Here is my code:

Main Form Code:

using System;
using System.Drawing;
using System.Collections;
using System.ComponentModel;
using System.Windows.Forms;
using System.Data;
using System.IO;
using System.Data.OleDb;
using System.Collections.Specialized;
using System.Text;
using System.Threading;

delegate void logAdd(string message);

namespace LCR_ShepherdStaffupdater_1._0
{
    public partial class Main : Form
    {
        public Main()
        {
            InitializeComponent();
        }

        public void add(string message)
        {
            this.Log.Items.Add(message);
        }
        public void logAdd(string message)
        {   /////////////////////////// COMPILER ERROR BELOW ///////////
            this.Invoke(new logAdd(add), new object[] { message }); // Compile error occurs here     
        }////////////////////////////// COMPILER ERROR ABOVE ///////////

        private void exitProgramToolStripMenuItem_Click(object sender, EventArgs e) 
        {
            Application.Exit(); 
        }
        private void aboutToolStripMenuItem1_Click(object sender, EventArgs e)
        {
            Form aboutBox = new AboutBox1(); 
            aboutBox.ShowDialog(); 
        }

        private void settingsToolStripMenuItem_Click(object sender, EventArgs e)
        {
        }

        private void settingsToolStripMenuItem1_Click(object sender, EventArgs e)
        {
            settingsForm.settings.ShowDialog();
        }

        private void synchronize_Click(object sender, EventArgs e)
        {
            string message = "Here my message is"; // changed this
            ErrorLogging.updateLog(message);  // changed this
        }

    }

    public class settingsForm 
    {
        public static Form settings = new Settings();
    }

}

Logging Class Code:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace LCR_ShepherdStaffupdater_1._0
{
    public class Logging
    {
        static Main mainClass = new Main();
        static logAdd logAddDelegate;

        public static void updateLog(string message)
        {
            logAddDelegate = mainClass.logAdd;
            logAddDelegate(message);
        }
    }
}
  • Compile Error:

    InvalidOperationException was unhandled - Invoke or BeginInvoke cannot be called on a control until the window handle has been created.

I already tried to create a handle on the Log item...but that didn't work. The problem is I have NO CLUE what I am doing and I have searched Google extensively only to find vague answers.

Please tell me how to create the handle before I invoke this delegate. While you are at it, give me some ways I can make this code more simple. For example, I dont want two Add functions... I had to do that because there was no way for me to find an item to invoke from the Logging class. Is there a better way to accomplish what I need to do?

Thank you!!!

EDIT:

My project is fairly large, but these are the only items causing this specific problem.

Log is my RichTextBox1 (Log.Items.Add(message)) I renamed it to Log so it is easier to retype.

I am calling updateLog(message) from a different form though...let me update that in here (although it makes no difference where I call updateLog(message) from it still gives me this error)

You guys are going to have to make things more simpler for me...and provide examples. I don't understand HALF of everything you guys are saying here...I have no clue on how to work with Invoking of methods and Handles. I've researched the crap out of it too...

SECOND EDIT:

I believe I have located the problem, but do not know how to fix it.

In my logging class I use this code to create mainClass:

static Main mainClass = new Main();

I am creating a entirely new blueprint replica to Main(), including Log (the richtextbox I am trying to update)

When I call updateLog(message) I believe I am trying to update the Log (richtextbox) on the second entity of Main() otherwise known as mainClass. Of course, doing so will throw me this exception because I haven't even seen that replica of the current Main I am using.

This is what I am shooting for, thanks to one of the people that gave an answer:

Main mainClass = Application.OpenForms.OfType<Main>().First();
logAddDelegate = mainClass.logAdd; 
logAddDelegate(message);

I need to create mainClass not with the new() operator because I dont want to create a new blueprint of the form I want to be able to edit the current form.

The above code doesn't work though, I can't even find Application. Is that even C# syntax?

If I can get the above code to work, I think I can resolve my issue and finally lay this problem to rest after a couple of HOURS of seeking for answers.

FINAL EDIT:

I figured it out thanks to one of the users below. Here is my updated code:

Main Form Code:

using System;
using System.Drawing;
using System.Collections;
using System.ComponentModel;
using System.Windows.Forms;
using System.Data;
using System.IO;
using System.Data.OleDb;
using System.Collections.Specialized;
using System.Text;
using System.Threading;

delegate void logAdd(string message);

namespace LCR_ShepherdStaffupdater_1._0
{
    public partial class Main : Form
    {
        private static Main mainFormForLogging;
        public static Main MainFormForLogging
        {
            get
            {
                return mainFormForLogging;
            }
        }

        public Main()
        {
            InitializeComponent();
            if (mainFormForLogging == null)
            {
                mainFormForLogging = this;
            }
        }

        public void add(string message)
        {
            this.Log.Items.Add(message);
        }
        public void logAdd(string message)
        {
            this.Log.BeginInvoke(new logAdd(add), new object[] { message });
        }

        private void exitProgramToolStripMenuItem_Click(object sender, EventArgs e) 
        {
            Application.Exit(); 
        }
        private void aboutToolStripMenuItem1_Click(object sender, EventArgs e)
        {
            Form aboutBox = new AboutBox1(); 
            aboutBox.ShowDialog(); 
        }

        private void settingsToolStripMenuItem_Click(object sender, EventArgs e)
        {
        }

        private void settingsToolStripMenuItem1_Click(object sender, EventArgs e)
        {
            settingsForm.settings.ShowDialog();
        }

        private void synchronize_Click(object sender, EventArgs e)
        {
            add("test");
            Logging.updateLog("testthisone");
            //DatabaseHandling.createDataSet();
        }

    }

    public class settingsForm 
    {
        public static Form settings = new Settings();
    }

}

Logging Class Code:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace LCR_ShepherdStaffupdater_1._0
{
    public class Logging
    {

        static Main mainClass = Main.MainFormForLogging;
        static logAdd logAddDelegate;

        public static void updateLog(string message)
        {
            logAddDelegate = mainClass.logAdd;
            logAddDelegate(message);
        }
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

I have solved this in the past using the following method:

private void invokeOnFormThread(MethodInvoker method)
{
    if (IsHandleCreated)
         Invoke(new EventHandler(delegate { method(); }));
    else
        method();
}

Call invokeOnFormThread instead of Invoke. It will only use the form's thread if a handle has already been created, otherwise it will use the caller's thread.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...