c++ - Range-for-statement cannot build range expression with array function parameter

Question

Why cannot build range expression passing an array as a function argument and using in a range-for-statement. Thanks for the help

void increment(int v[]){
    // No problem
    int w[10] = {9,8,7,6,5,4,3,2,1,9};
    for(int& x:w){
        std::cout<<"range-for-statement: "<<++x<<"
";
    }

    // error: cannot build range expression with array function 
    // parameter 'v' since parameter with array type 'int []' is 
    // treated as pointer type 'int *'
    for(int x:v){
        std::cout<<"printing "<<x<<"
";
    }

    // No problem
    for (int i = 0; i < 10; i++){
        int* p = &v[i];             
    }
}

int main()
{
    int v[10] = {9,8,7,6,5,4,3,2,1,9};
    increment(v);
}

Answer 1

Despite appearances, v is a pointer not an array - as the error message says. Built-in arrays are weird things, which can't be copied or passed by value, and silently turn into pointers at awkward moments.

There is no way to know the size of the array it points to, so no way to generate a loop to iterate over it. Options include:

• use a proper range-style container, like std::array or std::vector
• pass the size of the array as an extra argument, and interate with an old-school loop