I want to get json with php encode function like the following
<?php
require "../classes/database.php";
$database = new database();
header("content-type: application/json");
$result = $database->get_by_name($_POST['q']); //$_POST['searchValue']
echo '{"results":[';
if($result)
{
$i = 1;
while($row = mysql_fetch_array($result))
{
if(count($row) > 1)
{
echo json_encode(array('id'=>$i, 'name' => $row['name']));
echo ",";
}
else
{
echo json_encode(array('id'=>$i, 'name' => $row['name']));
}
$i++;
}
}
else
{
$value = "FALSE";
echo json_encode(array('id'=>1, 'name' => "")); // output the json code
}
echo "]}";
i want the output json to be something like that
{"results":[{"id":1,"name":"name1"},{"id":2,"name":"name2"}]}
but the output json is look like the following
{"results":[{"id":1,"name":"name1"},{"id":2,"name":"name2"},]}
As you realize that there is comma at the end, i want to remove it so it can be right json syntax, if i removed the echo ",";
when there's more than one result the json will generate like this {"results":[{"id":1,"name":"name1"}{"id":2,"name":"name2"}]}
and that syntax is wrong too
Hope that everybody got what i mean here, any ideas would be appreciated
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