c++ - Move semantics & returning const values

Question

I have the habit (?!?!?) of returning everything as a "const" value. Like this...

struct s;

s const make_s();

s const &s0 = make_s();
s const s1 = make_s();

With move operations and r-value references and the following functions...

void take_s(s &&s0);
void take_s(s const &&s0);  //  Doesn't make sense

I can no longer write...

take_s(make_s());

The main reason I started using the convention of returning const values is to prevent someone from writing code like this...

make_s().mutating_member_function();

The use case is the following...

struct c_str_proxy {
    std::string m_s;

    c_str_proxy(std::string &&s) : m_s(std::move(s)) {
    }
};

c_str_proxy c_str(std::string &&s) {
    return c_str_proxy(s);
}

char const * const c_str(std::string const &s) {
    return s.c_str();
}

std::vector < std::string > const &v = make_v();
std::puts(c_str(boost::join(v, ", ")));

std::string const my_join(std::vector < std::string > const &v, char const *sep);

//  THE FOLLOWING WORKS, BUT I THINK THAT IS ACCIDENTAL
//  IT CALLS
//
//      c_str(std::string const &);
//
//  BUT I THINK THE TEMPORARY RETURNED BY
//
//      my_join(v, "; ")
//
//  IS NO LONGER ALIVE BY THE TIME WE ARE INSIDE
//
//      std::puts
//
//  AS WE ARE TAKING THE "c_str()" OF A TEMPORARY "std::string"
//
std::puts(c_str(my_join(v, "; ")));

Looks as if "returning const value" and r-value references don't mix in this particular use case. Is that right?

**Edit 0: Extra question...**

The object is temporary anyway. Why should "const" prevent moving? Why can't we move "const" temporaries?

Answer 1

You have two conflicting goals. On one hand, you want to prevent modifications from being made to the returned object, but on the other hand, you want to allow modifications to be made (that's what a move operation is. It modifies the source object, by stealing its internal resources).

You need to make up your mind. Do you want the object to be immutable, or do you want people to be able to modify it?

For what it's worth, I don't really see what you'd gain by returning const temporaries in the first place. Yes, you prevent people from calling a mutating member function on it, but why would you want to? At best, being able to do so can be useful, and at worst, it's a mistake that is easily avoided.

And what you're doing doesn't really make much sense. The entire point in a temporary is that it's going to go away in a moment, so who cares if it gets modified?

The entire idea behind rvalue references and move semantics is that temporaries are temporary, and so they can be modified without harming anyone.