a
is sorted, but the method sorts the array in place. Read the signature of sort
: sort
takes &mut self
and returns unit (i.e. nothing), so when you print s
, you print ()
.
Working code:
fn main() {
let mut a = [1, 3, 2];
a.sort();
assert_eq!(a, [1, 2, 3]);
println!("{:?}", a);
}
Writing a function that returns a sorted array
You can write a function that does what you want:
fn sort<A, T>(mut array: A) -> A
where
A: AsMut<[T]>,
T: Ord,
{
let slice = array.as_mut();
slice.sort();
array
}
fn main() {
let a = [1, 3, 2];
assert_eq!(sort(a), [1, 2, 3]);
}
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