Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
506 views
in Technique[技术] by (71.8m points)

css - LESS mixin - Output values without quotes

I am trying to write a LESS mixin with multiple input parameter values for CSS transforms. The input values are the type of transformation to be done and the value associated with the transformation.

For example, consider the code given below:

.transform(@type; @value){
}

If I give input as type='rotateY' and value='360deg', the output should be transform: rotateY(360deg). I have tried the below options but none of them seem to be working (output is mentioned as comment).

transform: "@{type}(@{value})"; /* Output: "rotateY(360deg)" */
transform: @{type}(@{value}); /* Output: Compiler error */
transform: @type(@value); /* Output: rotateY 360deg */

How should I code it to get the output as required? Please help.

Note: The mixin code has a lot of other items also, I have posted just the line that needs fixing.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Just escape the string using ~ like shown below. Doing this would make sure that the quotes are not printed in the output CSS.

Input Code:

transform: ~"@{type}(@{value})";

or

transform: e("@{type}(@{value})");

Mixin Call:

.transform(rotateY;360deg);

Output CSS:

transform: rotateY(360deg);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...