Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
178 views
in Technique[技术] by (71.8m points)

c++ - Why Doesn't string::data() Provide a Mutable char*?

In array, string, and vector all got the data method which:

Returns pointer to the underlying array serving as element storage. The pointer is such that range [data(); data() + size()) is always a valid range, even if the container is empty. [Source]

This method is provided in a mutable and const version for all applicable containers, for example:

T* vector<T>::data();
const T* vector<T>::data() const;

All applicable containers, that is, except string which only provides the const version:

const char* string::data() const;

What happened here? Why did string get shortchanged, when char* string::data() would be so helpful?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

The short answer is that does provide the char* string::data() method. Which is vital for the similarly data function, thus to gain mutable access to the underlying C-String I can now do this:

auto foo = "lorem ipsum"s;

for(auto i = data(foo); *i != ''; ++i) ++(*i);

For historical purposes it's worth chronicling string's development which is building upon: In access to string's underlying buffer is made possible possible by a new requirement that it's elements are stored contiguously such that for any given string s:

&*(s.begin() + n) == &*s.begin() + n for any n in [0, s.size()), or, equivalently, a pointer to s[0] can be passed to functions that expect a pointer to the first element of a CharT[] array.

Mutable access to this newly required underlying C-String was obtainable by various methods, for example: &s.front(), &s[0], or &*s.first() But back to the original question which would avoid the burden of using one of these options: Why hasn't access to string's underlying buffer been provided in the form of char* string::data()?

To answer that it is important to note that T* array<T>::data() and T* vector<T>::data() were an addition required by . No additional requirements were incurred by against other contiguous containers such as deque. And there certainly wasn't an additional requirement for string, in fact the requirement that string was contiguous was new to . Before this const char* string::data() had existed. Though it explicitly was not guaranteed to be pointing to any underlying buffer, it was the only way to obtain a const char* from a string:

The returned array is not required to be null-terminated.

This means that string was not "shortchanged" in 's transition to data accessors, it simply was not included thus only the const data accesor that string previously possessed persisted. There are naturally occurring examples in C++11's implementation which necessitate writing directly to the underlying buffer of a string.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

2.1m questions

2.1m answers

60 comments

56.9k users

...