In a pandas dataframe created like this:
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.randint(10, size=(6, 6)),
columns=['c' + str(i) for i in range(6)],
index=["r" + str(i) for i in range(6)])
which could look as follows:
c0 c1 c2 c3 c4 c5
r0 2 7 3 3 2 8
r1 6 9 6 7 9 1
r2 4 0 9 8 4 2
r3 9 0 4 3 5 4
r4 7 6 8 8 0 8
r5 0 6 1 8 2 2
I can easily select certain rows and/or a range of columns using .loc
:
print df.loc[['r1', 'r5'], 'c1':'c4']
That would return:
c1 c2 c3 c4
r1 9 6 7 9
r5 6 1 8 2
So, particular rows/columns I can select in a list, a range of rows/columns using a colon.
How would one do this in R? Here and here one always has to specify the desired range of columns by their index but one cannot - or at least I did not find it - access those by name. To give an example:
df <- data.frame(c1=1:6, c2=2:7, c3=3:8, c4=4:9, c5=5:10, c6=6:11)
rownames(df) <- c('r1', 'r2', 'r3', 'r4', 'r5', 'r6')
The command
df[c('r1', 'r5'),'c1':'c4']
does not work and throws an error. The only thing that worked for me is
df[c('r1', 'r5'), 1:4]
which returns
c1 c2 c3 c4
r1 1 2 3 4
r5 5 6 7 8
But how would I select the columns by their name and not by their index (which might be important when I drop certain columns throughout the analysis)? In this particular case I could of course use grep
but how about columns that have arbitrary names?
So I don't want to use
df[c('r1', 'r5'),c('c1','c2', 'c3', 'c4')]
but an actual slice.
EDIT:
A follow-up question can be found here.
See Question&Answers more detail:
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