format - How to display hexadecimal numbers in C?

Question

I have a list of numbers as below:

0, 16, 32, 48 ...

I need to output those numbers in hexadecimal as:

0000,0010,0020,0030,0040 ...

I have tried solution such as:

printf("%.4x",a); // where a is an integer

but the result that I got is:

0000, 0001, 0002, 0003, 0004 ...

I think I'm close there. Can anybody help as I'm not so good at printf in C.

Thanks.

Answer 1

Try:

printf("%04x",a);

• 0 - Left-pads the number with zeroes (0) instead of spaces, where padding is specified.
• 4 (width) - Minimum number of characters to be printed. If the value to be printed is shorter than this number, the result is right justified within this width by padding on the left with the pad character. By default this is a blank space, but the leading zero we used specifies a zero as the pad char. The value is not truncated even if the result is larger.
• x - Specifier for hexadecimal integer.

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