Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
358 views
in Technique[技术] by (71.8m points)

android - Paging Library Filter/Search

I am using the Android Paging Library like described here: https://developer.android.com/topic/libraries/architecture/paging.html

But i also have an EditText for searching Users by Name.

How can i filter the results from the Paging library to display only matching Users?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can solve this with a MediatorLiveData.

Specifically Transformations.switchMap.

// original code, improved later
public void reloadTasks() {
    if(liveResults != null) {
        liveResults.removeObserver(this);
    }
    liveResults = getFilteredResults();
    liveResults.observeForever(this);
}

But if you think about it, you should be able to solve this without use of observeForever, especially if we consider that switchMap is also doing something similar.

So what we need is a LiveData<SelectedOption> that is switch-mapped to the LiveData<PagedList<T>> that we need.

private final MutableLiveData<String> filterText = savedStateHandle.getLiveData("filterText")

private final LiveData<List<T>> data;

public MyViewModel() {
    data = Transformations.switchMap(
            filterText,
            (input) -> { 
                if(input == null || input.equals("")) { 
                    return repository.getData(); 
                } else { 
                    return repository.getFilteredData(input); }
                }
            });
  }

  public LiveData<List<T>> getData() {
      return data;
  }

This way the actual changes from one to another are handled by a MediatorLiveData.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

2.1m questions

2.1m answers

60 comments

57.0k users

...