Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
457 views
in Technique[技术] by (71.8m points)

encryption - How do I compute the approximate entropy of a bit string?

Is there a standard way to do this?

Googling -- "approximate entropy" bits -- uncovers multiple academic papers but I'd like to just find a chunk of pseudocode defining the approximate entropy for a given bit string of arbitrary length.

(In case this is easier said than done and it depends on the application, my application involves 16,320 bits of encrypted data (cyphertext). But encrypted as a puzzle and not meant to be impossible to crack. I thought I'd first check the entropy but couldn't easily find a good definition of such. So it seemed like a question that ought to be on StackOverflow! Ideas for where to begin with de-cyphering 16k random-seeming bits are also welcome...)

See also this related question:
What is the computer science definition of entropy?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Entropy is not a property of the string you got, but of the strings you could have obtained instead. In other words, it qualifies the process by which the string was generated.

In the simple case, you get one string among a set of N possible strings, where each string has the same probability of being chosen than every other, i.e. 1/N. In the situation, the string is said to have an entropy of N. The entropy is often expressed in bits, which is a logarithmic scale: an entropy of "n bits" is an entropy equal to 2n.

For instance: I like to generate my passwords as two lowercase letters, then two digits, then two lowercase letters, and finally two digits (e.g. va85mw24). Letters and digits are chosen randomly, uniformly, and independently of each other. This process may produce 26*26*10*10*26*26*10*10 = 4569760000 distinct passwords, and all these passwords have equal chances to be selected. The entropy of such a password is then 4569760000, which means about 32.1 bits.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...