iphone - Get Cell position in UITableview

Question

I am trying to get position of cell in tableview. from this code i am getting cell position

int numberOfSections = [UITableView numberOfSections];
int numberOfRows = 0;
NSIndexPath *tempIndexPath = nil;
UITableViewCell *tempCell = nil;
for(int i=0;i<numberOfSections;i++)
{
     numberOfRows = [UITableView numberOfRowsInSection:i];
     for(int j=0;j<numberOfRows;j++
     {
           tempIndexPath = [NSIndexPath indexPathForRow:j inSection:i];
           tempCell = [UITableView cellForRowAtIndexPath:tempIndexPath];
           NSLog("Y postion for cell at (Row = %d,Section = %d) is :%f",tempCell.frame.origin.y);
     }  
}

it is calculating y axes of cell in tableview but my problem is i want to get the cell position in the visible area of tableview rect. ie if table view has size cgrectmake(0,0,200,500) and cell height is 100 pixels. so tableview will show 5 rows. if i scroll down and select 7th row. i will get its y axes 700. but the cell will be within (0,0,200,500) frame. How can I get cell location within this frame (0,0,200,500).

Answer 1

To get the position of a UITableViewCell relative to the view, in which the tableView is located (e.g. relative to your visible area):

Swift 5 (and also Swift 4, Swift 3):

let rectOfCellInTableView = tableView.rectForRow(at: indexPath)
let rectOfCellInSuperview = tableView.convert(rectOfCellInTableView, to: tableView.superview)
    
print("Y of Cell is: (rectOfCellInSuperview.origin.y)")

Objective-C:

CGRect rectOfCellInTableView = [tableView rectForRowAtIndexPath: indexPath];
CGRect rectOfCellInSuperview = [tableView convertRect: rectOfCellInTableView toView: tableView.superview];

NSLog(@"Y of Cell is: %f", rectOfCellInSuperview.origin.y);

Swift 2 (really?):

let rectOfCellInTableView = tableView.rectForRowAtIndexPath(indexPath)
let rectOfCellInSuperview = tableView.convertRect(rectOfCellInTableView, toView: tableView.superview)

print("Y of Cell is: (rectOfCellInSuperview.origin.y)")