c++ - opencv read jpeg image from buffer

Question

I have an unsigned char* buffer containing data of a jpeg image. I would like to display that image using c++ and opencv. If i do:

Mat img(Size(640, 480), CV_8UC3, data);
namedWindow("image", 1);
imShow("image", img);

I get a noisy mess of pixels.

I suppose it's because the data is jpeg (with a header). Because this works:

Mat imgbuf(Size(640, 480), CV_8UC3, data);
Mat img = imdecode(imgbuf, CV_LOAD_IMAGE_COLOR);

BUT I cannot use the imdecode function as it is from highgui.h which is based upon GTK 2, and in my project I use GTK 3.

So, how can I display the buffer data? Is there a way to decode the jpeg image other than imdecode in opencv, if that's the problem. I don't really want to have to rebuild opencv with Qt...

Any other suggestions?

(Using Linux)

Answer 1

I have seen many responses to this question around on the net saying that you should call libjpeg directly and bypass OpenCV's imread() routine.

This is NOT necessary! You can use imdecode() to decode a raw image buffer from memory. The way to do it is NOT intuitive, and isn't documented enough to help people trying to do this for the first time.

If you have a pointer/size for your raw file data (fread() directly from the .jpg, .png, .tif, files, etc...

int    nSize = ...       // Size of buffer
uchar* pcBuffer = ...    // Raw buffer data


// Create a Size(1, nSize) Mat object of 8-bit, single-byte elements
Mat rawData( 1, nSize, CV_8UC1, (void*)pcBuffer );

Mat decodedImage  =  imdecode( rawData /*, flags */ );
if ( decodedImage.data == NULL )   
{
    // Error reading raw image data
}

That's IT!

Hope this helps someone in the future.