swift2 - How to "strongify" optional self using guard in Swift 2.0

Question

There's a similar question about how to weakify/strongify self, which is answered, but I'm wondering how to use "self" without rightward-drifting caused by if let:

Welcome to Apple Swift version 2.0 (700.0.59 700.0.72). Type :help for assistance.
  2> import Foundation
  3> class Foo {
  4.     func guardOptSelf() -> () throws -> Void {
  5.         return { [weak self] in
  6.             guard let self = self else { throw NSError(domain: "I was destroyed!", code: 1, userInfo: nil) }
  7.             self.doSomethingNonOptionalSelf()         
  8.         }
  9.     }
  10. }
repl.swift:6:19: error: pattern matching in a condition requires the 'case' keyword
            guard let self = self else { throw NSError(domain: "I was destroyed!", code: 1, userInfo: nil) }
                  ^
                  case
repl.swift:6:23: error: binary operator '~=' cannot be applied to two 'Foo?' operands
            guard let self = self else { throw NSError(domain: "I was destroyed!", code: 1, userInfo: nil) }

Answer 1

You can shadow self; you just need backticks to indicate that "you know what you're doing". For example:

foo.doSomethingAsyncWithBar(bar) { [weak self] result in
    guard let `self` = self else { return }
    self.receivedResult(result)
}

Or, in your example:

2> import Foundation
3> class Foo {
4.     func guardOptSelf() -> () throws -> Void {
5.         return { [weak self] in
6.             guard let `self` = self else { throw NSError(domain: "I was destroyed!", code: 1, userInfo: nil) }
7.             self.doSomethingNonOptionalSelf()         
8.         }
9.     }
10. }