linux - Why does ps o/p list the grep process after the pipe?

Question

When I do

$ ps -ef | grep cron

I get

root      1036     1  0 Jul28 ?        00:00:00 cron
abc    21025 14334  0 19:15 pts/2    00:00:00 grep --color=auto cron

My question is why do I see the second line. From my understanding, ps lists the processes and pipes the list to grep. grep hasn't even started running while ps is listing processes, then how come grep process is listed in the o/p ?

Related second question:

When I do

$ ps -ef | grep [c]ron

I get only

root      1036     1  0 Jul28 ?        00:00:00 cron

What is the difference between first and second grep executions?

Answer 1

When you execute the command:

ps -ef | grep cron

the shell you are using

(...I assume bash in your case, due to the color attribute of grep I think you are running a gnu system like a linux distribution, but it's the same on other unix/shell as well...)

will execute the pipe() call to create a FIFO, then it will fork() (make a running copy of itself). This will create a new child process. This new generated child process will close() its standard output file descriptor (fd 1) and attach the fd 1 to the write side of the pipe created by the father process (the shell where you executed the command). This is possible because the fork() syscall will maintain, for each, a valid open file descriptor (the pipe fd in this case). After doing so it will exec() the first (in your case) ps command found in your PATH environment variable. With the exec() call the process will become the command you executed.

So, you now have the shell process with a child that is, in your case, the ps command with -ef attributes.

At this point, the parent (the shell) fork()s again. This newly generated child process close()s its standard input file descriptor (fd 0) and attaches the fd 0 to the read side of the pipe created by the father process (the shell where you executed the command).

After doing so it will exec() the first (in your case) grep command found in your PATH environment variable.

Now you have the shell process with two children (that are siblings) where the first one is the ps command with -ef attributes and the second one is the grep command with the cron attribute. The read side of the pipe is attached to the STDIN of the grep command and the write side is attached to the STDOUT of the ps command: the standard output of the ps command is attached to the standard input of the grep command.

Since ps is written to send on the standard output info on each running process, while grep is written to get on its standard input something that has to match a given pattern, you'll have the answer to your first question:

1. the shell runs: ps -ef;
2. the shell runs: grep cron;
3. ps sends data (that even contains the string "grep cron") to grep
4. grep matches its search pattern from the STDIN and it matches the string "grep cron" because of the "cron" attribute you passed in to grep: you are instructing grep to match the "cron" string and it does because "grep cron" is a string returned by ps at the time grep has started its execution.

When you execute:

ps -ef | grep '[c]ron'

the attribute passed instructs grep to match something containing "c" followed by "ron". Like the first example, but in this case it will break the match string returned by ps because:

1. the shell runs: ps -ef;
2. the shell runs: grep [c]ron;
3. ps sends data (that even contains the string grep [c]ron) to grep
4. grep does not match its search pattern from the stdin because a string containing "c" followed by "ron" it's not found, but it has found a string containing "c" followed by "]ron"

GNU grep does not have any string matching limit, and on some platforms (I think Solaris, HPUX, aix) the limit of the string is given by the "$COLUMN" variable or by the terminal's screen width.

Hopefully this long response clarifies the shell pipe process a bit.

TIP:

ps -ef | grep cron | grep -v grep