c++ - How do I strip a tuple<> back into a variadic template list of types?

Question

Is there a way to strip a std::tuple<T...> in order to get it back to T...?

Example

Suppose vct<T...> is a pre-existing variadic class template,

using U = std::tuple<int,char,std::string>;
using X = vct<int,char,std::string>;
using Y = vct< strip<U> >;            // should be same as X

Notes

I know about std::tuple_element, but I need all the elements, in a form that is usable as T...

For reference, I have found this question, which is similar, but my needs are somewhat simpler (so I hope there is a simpler solution): all I need is the list of types that are in the tuple - I don't care about the actual values of a tuple instance.

Answer 1

template<typename>
struct strip;

template<typename ...T>
struct strip<std::tuple<T...>>
{
   using type = vct<T...>;
};

then use this as:

using Y = strip<U>::type;

Now Y is same as X.