I need to detect the Sun from the space sky.
These are examples of the input images:
I've got such results after Morphologic filtering ( open
operation for twice )
Here's the algorithm code of this processing:
// Color to Gray
cvCvtColor(image, gray, CV_RGB2GRAY);
// color threshold
cvThreshold(gray,gray,150,255,CV_THRESH_BINARY);
// Morphologic open for 2 times
cvMorphologyEx( gray, dst, NULL, CV_SHAPE_RECT, CV_MOP_OPEN, 2);
Isn't it too heavy processing for such a simple task? And how to find the center of the Sun? If I find white points, than I'll find white points of big Earth ( left top corner on first example image )
Please advise me please my further action to detect the Sun.
UPDATE 1:
Trying algorithm of getting centroid
by formula : {x,y} = {M10/M00, M01/M00}
CvMoments moments;
cvMoments(dst, &moments, 1);
double m00, m10, m01;
m00 = cvGetSpatialMoment(&moments, 0,0);
m10 = cvGetSpatialMoment(&moments, 1,0);
m01 = cvGetSpatialMoment(&moments, 0,1);
// calculating centroid
float centroid_x = m10/m00;
float centroid_y = m01/m00;
cvCircle( image,
cvPoint(cvRound(centroid_x), cvRound(centroid_y)),
50, CV_RGB(125,125,0), 4, 8,0);
And where Earth is in the photo, I got such a result:
So, centroid is on the Earth. :(
UPDATE 2:
Trying cvHoughCircles
:
CvMemStorage* storage = cvCreateMemStorage(0);
CvSeq* circles = cvHoughCircles(dst, storage, CV_HOUGH_GRADIENT, 12,
dst->width/2, 255, 100, 0, 35);
if ( circles->total > 0 ) {
// getting first found circle
float* circle = (float*)cvGetSeqElem( circles, 0 );
// Drawing:
// green center dot
cvCircle( image, cvPoint(cvRound(circle[0]),cvRound(circle[1])),
3, CV_RGB(0,255,0), -1, 8, 0 );
// wrapping red circle
cvCircle( image, cvPoint(cvRound(circle[0]),cvRound(circle[1])),
cvRound(circle[2]), CV_RGB(255,0,0), 3, 8, 0 );
}
First example: bingo, but the second - no ;(
I've tried different configuration of cvHoughCircles()
- couldn't find configuration to fit every my example photo.
UPDATE3:
matchTemplate
approach worked for me ( response of mevatron
). It worked with big number of tests.
See Question&Answers more detail:
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