If the numeric part is always at the beginning, then you can use this:
PATINDEX('%[0-9][^0-9]%', ConcUnit)
to get the index of the last digit.
Thus, this:
DECLARE @str VARCHAR(MAX) = '4000 ug/ML'
SELECT LEFT(@str, PATINDEX('%[0-9][^0-9]%', @str )) AS Number,
LTRIM(RIGHT(@str, LEN(@str) - PATINDEX('%[0-9][^0-9]%', @str ))) As Unit
gives you:
Number Unit
-------------
4000 ug/ML
EDIT:
If numeric data include double values as well, then you can use this:
SELECT LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))
to get the index of the last digit.
Thus, this:
SELECT LEFT(@str, LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str)))
gives you the numeric part.
And this:
SELECT LEFT(@str, LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))) AS Numeric,
CASE
WHEN CHARINDEX ('%', @str) <> 0 THEN LTRIM(RIGHT(@str, LEN(@str) - CHARINDEX ('%', @str)))
ELSE LTRIM(RIGHT(@str, PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))))
END AS Unit
gives you both numberic and unit part.
Here are some tests that I made with the data you have posted:
Input:
DECLARE @str VARCHAR(MAX) = '50 000ug/ML'
Output:
Numeric Unit
------------
50 000 ug/ML
Input:
DECLARE @str VARCHAR(MAX) = '99.5%'
Output:
Numeric Unit
------------
99.5
Input:
DECLARE @str VARCHAR(MAX) = '4000 . 35 % ug/ML'
Output:
Numeric Unit
------------------
4000 . 35 ug/ML